30p^2+p=7p

Solution for 30p^2+p=7p equation:

30p^2+p=7p

We move all terms to the left:

30p^2+p-(7p)=0

We add all the numbers together, and all the variables

30p^2-6p=0

a = 30; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·30·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*30}=\frac{0}{60}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*30}=\frac{12}{60}
=1/5
$